Description
F(x)= x3+8x2-x-8
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Explanation & Answer
ANSWER = ROOTS ARE -1, 1 , -8
F(x)= x^3+8 x^2-x-8
=(x^3+8 x^2)+(−x−8)
=x^2(x+8)−1(x+8)
=(x^2−1)(x+8)
a^2 - b^2 = (a+ b)(a - b)
so,
(x^2−1^2) = (x+1) (x -1)
substituting this in the above equation
F(x)= (x^2−1)(x+8)
=(x+1) (x -1)(x+8).....
so (x+1)=0 or (x -1) = 0 or (x+8) = 0
x = -1 or x = 1 or x = - 8
thus the roots are -1, 1 , -8..................................ANSWER
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