How many L of 0.5 M HCl would it take to titrate 400 g of KOH?
The molecule weight of KOH is 56.1g/mol, 400g is 400/56.1 = 7.13 moles
KOH +HCl = KCl+ H2O
the number of moles for KOH and HCl in the reaction is 1:1, thus we need 7.13 moles HCl, this is up to
7.13/0.5 = 14.26 L of HCl
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