what is the answer to this problem?

label Algebra
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schedule 1 Day
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27x^6+64y^12
Apr 30th, 2015

I assume you need to factorize.

27x^6+64y^12

This is of the form a^3+b^3 = (a+b) (a^2-ab+b^2) 

      so  27x^6+64y^12 = (3x^2 + 4y^4)^3 =   (3x^2 + 4y^4) (9x^4-12x^2y^4+ 16y^8)   


Please let me know if you have any other questions and best me if you are satisfactory.
   

 

Apr 30th, 2015

It didn't say what needed to be done, but I assume that it is factor. Thank you that was great. I couldn't figure it out

Apr 30th, 2015

(3x^2 + 4y^4) (9x^4-12x^2y^4+ 16y^8)

Apr 30th, 2015

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Apr 30th, 2015
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Apr 30th, 2015
Jun 26th, 2017
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