I assume you need to factorize.
This is of the form a^3+b^3 = (a+b) (a^2-ab+b^2)
so 27x^6+64y^12 = (3x^2 + 4y^4)^3 = (3x^2 + 4y^4) (9x^4-12x^2y^4+ 16y^8)
Please let me know if you have any other questions and best me if you are satisfactory.
It didn't say what needed to be done, but I assume that it is factor. Thank you that was great. I couldn't figure it out
(3x^2 + 4y^4) (9x^4-12x^2y^4+ 16y^8)
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