how many seconds will it take for a police car to intercept a speeder

Algebra
Tutor: None Selected Time limit: 1 Day

the speeder is moving a constant velocity of 18 meters per second. the patrol car starts  from a still position and accelerates at a rate of 5 meters per second . using s(f) a function of distance find how many seconds it will take the patrol car to intercept the speeder let a = acceleration in meters per second squared =time in seconds. v=velocity in meters per second speeders distance s(t) =vt and patrol car distance s(t)=1/2at^2

Apr 30th, 2015

distance covered is equal

1/2a t^2=vt
1/2*5*t^2=18t

5t^2-36t=0

t=0

or t=2.683 seconds

Apr 30th, 2015

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Apr 30th, 2015
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Apr 30th, 2015
May 25th, 2017
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