Solve the equation for x and y (x-3)^2=.2(y-(-10))

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I have what X and Y are but my teacher says I need to solve the equation for the points and I dont know how to do that. X=2.065 and Y=-5.633

HOW DO I SOLVE THE EQUATION AND GET THOSE ANSWERS?? HELP 

May 1st, 2015

Isolate x on one side and isolate y on one side to solve for each.. Solve for y:      (x-3)^2=.2(y-(-10);

(x-3)^2=.2(y+10); (x-3)^2=.2y+2 ; .2y=(x-3)^2-2; y=((x-3)^2-2)/5

Solve for x:(x-3)^2=.2(y-(-10); |x-3|=sqrt(.2(y+10)); x-3=sqrt(.2(y+10))    or 3-x=sqrt(.2(y+10))        .

x=sqrt(.2(y+10))   or x=3-sqrt(.2(y+10))  . Your stated x and y do not work. (2.065-3)^2=.874 ; .2(-.5633-(-10))=1.887  .          . 

May 1st, 2015

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