ANSWER IS

OPTION C. ( -6, 8)

reflection image of P(0, 0) , first across x = -3 , results in change of x value by, - 3 + ( 0 - 3) and y value remains constant

reflection image of P(0, 0) , first across x = -3

= ( - 6,0)

reflection image of P(- 6, 0) then across y = 4?

value of x remain constant and y changes by 4 + 4-0=8

reflection image of P(- 6, 0) then across y = 4

= ( -6, 8).................................................ANSWER

hope you understood..please message if you have any doubts...thank you

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