Line BC is the diameter of circle D. Find <BAD if ARC mAB is 110 degrees.

If arc mAB = 110 and center is D , then <BDA = 110

Join A and B to get triangle BDA which is an isoceles triangle since BD = DA and <DBA =<BAD

Let <DBA =<DAB =x

so x+x+110 =180

2x =70

x=70/2 =35

so <BAD =35 degree

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