what is the answer to this

Mathematics
Tutor: None Selected Time limit: 1 Day

2x^2+3xy-4x^2       x=2 y=4

May 1st, 2015

2x^2+3xy-4x^2 

Substitute  x=2 and  y=4 in the equation,

 So 2x^2+3xy-4x^2   = 2 *2^2+3*2*4-4*2^2

                                  =   8+24-16

                                  =16

Please let me know if you have any other questions and best me if you are satisfactory.   

May 1st, 2015

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