1. foci is (sqrt 33,0), (-sqrt33,0)
graph is Screen Shot 2015-05-01 at 2.25.13 AM.png
2. equation is x^2/49 + y^2/13 =1
If you have any questions let me know
Is it possible u could so it by hand because I still n don't understand it like step by step
hey could u show how you got the work like show ur work likes the main thing i want to know how to do the problem
general form of the ellipse is x^2/a+y^2/b=1
foci is sqrt(a-b)
so in a. we can see that a=49, b=16, a-b=31
so foci is sqrt 31 and -sqrt 31
for b. foci are the x-intercepts, then you can find vertices which is b
let me know if you have more questions
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