how do i solve for "what is the equation of a line passing through the point (6,2) that is perpendictular to y= 2/3x-8
The slope intercept form of a line is
y = mx + c
where m is the slope of the line
and c is the y-intercept.
Comparing the above two equations we get
Slope, m =
If two lines are perpendicular then product of their slopes is -1.
Let m' be the slope of the perpendicular line.
For finding the equation of the perpendicular line we can use the point slope form of a line which is
and is a point on the line.
Here, m is the slope of the perpendicular line
m = m' = -3/2
= (6, 2)
So equation of the perpendicular line is
Equation of perpendicular line passing through (6, 2) is
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