how do i solve for "what is the equation of a line passing through the point (6,2) that is perpendictular to y= 2/3x-8

The slope intercept form of a line is

y = mx + c

where m is the slope of the line

and c is the y-intercept.

Comparing the above two equations we get

Slope, m =

If two lines are perpendicular then product of their slopes is -1.

Let m' be the slope of the perpendicular line.

So,

For finding the equation of the perpendicular line we can use the point slope form of a line which is

and is a point on the line.

Here, m is the slope of the perpendicular line

m = m' = -3/2

= (6, 2)

So equation of the perpendicular line is

ANSWER:

Equation of perpendicular line passing through (6, 2) is

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