unit 6 coordinate geometry test [540772]

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how do i solve for "what is the equation of a line passing through the point (6,2) that is perpendictular to y= 2/3x-8

May 1st, 2015


The slope intercept form of a line is 

y = mx + c

where m is the slope of the line

and c is the y-intercept.


Comparing the above two equations we get 

Slope, m = 


If two lines are perpendicular then product of their slopes is -1.

Let m' be the slope of the perpendicular line.

So, 

 


For finding the equation of the perpendicular line we can use the point slope form of a line which is


where m is the slope of the line

and  is a point on the line.


Here, m is the slope of the perpendicular line

m = m' = -3/2

 = (6, 2)


So equation of the perpendicular line is



ANSWER:

Equation of perpendicular line passing through (6, 2) is


May 1st, 2015

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