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xnaqev95

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i upload two documents and the first one for pre-lab assignment that has 5 questions.

the other one is about Lenses and Mirrors and you will see in the second page the 8 questions that it need to be solved.


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Summary: Lenses and Mirrors Equations (1) Lenses redirect light by refraction. Converging lenses are thicker in the middle and bring light rays together. Diverging lenses are thinner in the middle and spread light out. Lens terminology is very similar to that of mirrors. An important difference is that when we consider a single lens, virtual images appear on the same side of the lens as the object, and real images appear on the opposite side. Another difference is that lenses have a focal point on each side. Ray diagrams for converging and diverging lenses are also similar to those for mirrors. And like mirrors, lenses have equations that quantify the relative size, orientation and distance of the images they produce. In addition, the lensmaker’s equation determines the focal length of a lens with differing radii of curvature on its two sides. Sign conventions can be trickier for lenses, so pay special attention to them. Several lenses can be used together to enhance their magnification properties, such as in a refracting telescopes. In a microscope, a lens called the objective creates a real image, which is used as the object for a second lens called the eyepiece. The viewer looks into the eyepiece and sees a final image that is inverted, virtual, and magnified. The human eye contains a lens that can change shape in order to create a focused image on the lightsensitive retina at the back of the eye. A person’s near point and far point are the closest and farthest distances on which she can focus. Sometimes a lens is specified by its refractive power, which is the inverse of its focal length. Refractive power P is measured in diopters, where 1 diopter = 1 m−1. This unit is commonly used with eyeglasses and contact lenses. The angular size of an object is the angle of the field of view that is taken up by the object. It is measured in radians, which allows the use of a small-angle approximation: For small angles, the angular size of an object is approximately its height divided by its distance. The angular magnification of a simple magnifier is the ratio of the angular size of the image to that of the object when the object is located at the near point of the human eye. Lenses can exhibit spherical aberration just as mirrors can. They also exhibit chromatic aberration due to the differing refractive indices of different wavelengths of light. Both kinds of aberration can cause an image to look blurry. You Do (due 11.23.17) Equations (2) 1. An object is placed between the focal point of a converging lens and a distance twice the focal length from the lens. Draw a ray diagram to determine the nature of the image and describe the image 2. An object is placed in front of a diverging lens. Draw a ray diagram to determine the nature of the image. 3. The focal length of a thin lens is 0.110 m. You want to use it to produce a real image at 0.600 meters from the lens. How far from the lens should the object be placed? ( 0.135 m) 4. The cornea and lens of the eye each refract light as it passes into the eye. We consider the cornea and lens together as one thin lens whose shape, and effective focal length, can be changed by the muscles around the eye. When incoming light is parallel, such as for an infinitely far away object, the eye muscles shape the effective lens to have a focal length of about 2.50 cm to produce a focused image on the retina. What focal length lens do the muscles cause to create a focused image of an object 35.0 cm away? (0.0233 m) 5. A child requires eyeglasses with diverging lenses, but is concerned that they will look too thick. The radius of curvature of the near surface of the lenses has a magnitude of 55.0 cm and the radius of curvature of the far surface has a magnitude of 35.0 cm. If the lenses are circular with a diameter of 5.00 cm and a thickness at the center of 0.100 cm, how thick are the glasses at the edge? (0.246 cm) 6. A concave spherical mirror is pointed at the Sun. Its radius of curvature is 2.50 m. The Sun subtends an angle of 0.533° in the sky. (a) What is the diameter of the image of the Sun created by the mirror? Hint: Use the magnification equations and the small angle approximation. (b) You want to use the mirror as a "solar cooker." If the intensity of sunlight incident on the mirror is 1.00×103 W/m2 and you want to supply energy to a large cooking pot at a rate of 255 W, what must be the circular "cross-sectional" area of the cooker? Note that this is not the area of the curved mirror, but of the planar circle that intercepts the sunlight, the imaginary lid that caps the mirrored bowl. (c) What intensity is produced at the image?( (a) 1.16 cm (b) 0.255 m2 (c) 2.41e6 W/m2 7. Elizabeth is nearsighted. Without glasses, she can see objects clearly when they are between 15.0 cm and 90.0 cm away from her eyes. Her glasses are designed to be worn 2.00 cm from her eyes, and have a focal length so that objects at infinity produce images at her far point. When she is wearing these glasses, how close to her eye can an object be before it appears out of focus? (17.3 cm) 8. A microscope has an objective lens focal length of 0.30 cm, an eyepiece focal length of 1.3 cm, and the two lenses are separated by 14 cm. Using an average nearpoint of 25 cm, what is the approximate overall magnification of the microscope? (−9.0e2) 40 LABORATORY 40 Reflection and Refraction with the Ray Box PRE-LABORATORY ASSIGNMENT 1. Define the index of refraction. 2. State the law of reflection. Use a diagram to define the angles involved. 3. State Snell's law. Define terms and angles using a diagram. 4. A light ray is incident on a plane interface between two media. The ray makes an incident angle with the normal of 25.0° in a medium of n=1.25. What is the angle that the refracted ray makes with the normal if the second medium has n= 1.552 Show your work. COPYRIGHT © 2008 Thomson Brooks/Cole 407 408 Physics Laboratory Manual Loyd 5. A 60.0° prism has an index of refraction of 1.45 as shown below. A ray is incident as shown at an angle of 60.0° to the normal of one of the prism faces. Trace the ray on through the prism and find the angles 02, 03, and 0, as defined in the laboratory instructions. Show your work. 760° n = 1.00 n = 1.00 Wonen 160 n = 1.45
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PRE-LABORATORY ASSIGNMENT
1.
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Reflection index is speed of light in a vacuum divide by seed of light in the medium.
𝐧=

2.
ϴi = ϴr
ϴi

ϴr...


Anonymous
I was having a hard time with this subject, and this was a great help.

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