determine the area under the standard normal curve that lies between Z= -0.88 and Z=0.88.
Z= -0.72 and Z=0
Z=-1.45 and Z=0.39
P(-0.88 <z < 0.88) = 0.6211
P(-0.72 <z < 0) = 0.2642
P(-1.45 <z < 0.39) = 0.5782
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?