what is the reference angle of -230 and how do you find it?
replace -230° by 130° (-230° + 360° = 130°) and observe that the angle is in the 2nd quadrant. So, the reference angle is the acute angle between the terminal side of the angle 130° and the negative x-axis (180°).
Thus, the answer is 180° - 130° = 50°.
if the angle is already positive do i still add 360 or do i just subtract it from 180?
At first, you need to determine in which quadrant is the angle. If it is positive but large than 360°, you may subtract an appropriate multiple of 360° and then choose the reference angle:
If the angle is in the 1st quadrant, then nothing else should be done e.g, ref. angle for 45° is 45°).
If the angle is in the 2nd quadrant, subtract it from 180° (as in the given example).
If the angle is in the 3rd quadrant, subtract 180° from it (e.g., ref. angle for 250° is 70°).
If the angle is in the 4th quadrant, subtract it from 360° (e.g., ref.angle for 300° is 60°)
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