Thomson Tube Experiment

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cncnl

Science

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Hi,

I am doing Thomson -e/m experiment. moreover, I want you to do the calculation for me. Furthermore, I want you to find out what is the error. uncertainty, standard divination, %differences, and average. I have uploaded the handout sheet that has all the things, and formulas you need to know. If a formula needs to be drive, please do. Show me all your work. do not pick this question if you do not know how to figure out everything. you need also to show me the method you used to finish each calculation ad statics. I am telling you from now because I do not want any issue with my assignment. If you are not a physics major do not pick this question. Thank you & Good luck,

REMEMBER THAT I WANT YOU TO SHOW ME ALL STEPS.

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10 Project No. Book No From Page No. TITLE A 13 n.320 ingle- Trial 2 • 271.7 V Irial i Vp V. - 4.39 KV It 0.1894 A Rx 6.35 cm 1.93.com Trial 3 V. 278.4V Va 4.60 kV IN 0.1863 A 1769.90 Vp. 249.5M IH-0.1835 A 1.636.10 • 4.4 kV em = 1.670.101 B:s 515 Create a plot final 2V 186)2 Ta Vp: 3477 76 Ve 1 Ix - 0.0 29 Trial 2 www Trial 1 Va 4.68 kV IH, - 0.288 A. t-5.05cm Botten Ino 0.3854 A * +32 cm Top Ihr 0.1710 A 4:52.8 mm Top In = 0.1706 A L.: CAL Bottom Trial 1.0.3039 A I 0.3039 A 1. 4.46 CM Betlost Lo = 4.23 cm Top To Page Date Date Vitnessed & Understood by me, Invented by Recorded by So, for A14 we used the equation e 2V (RB) m Which was in the handout. R is derived a little bit later, and is given by V24² + L? R= 2 A-L With A being the length of one side of the diamond, which was 80 mm. We recorded two values of L for each trial, one where the beam was deflected up, and one where it was deflected down with the reverse current. The value for L that you should use in this equation is the average of the two. So for each trial, just average both of the values for L, use that in equation to find R, and then use that in the first equation to find e/m.
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Anonymous
Awesome! Made my life easier.

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