So 3 is a special case where we get an imaginary number which can be expressed two ways.

theta=

1.57079632679489661923132169163975144209858469968755291048747... -
1.76274717403908605046521864995958461805632065652327082150659... i
(result in radians)

OR
r = 2.36108 (radius), theta = -48.2955° (angle)

Please let me know if you have any questions! Hope this helps!

May 2nd, 2015

ok so second approach, let's factor it

we get

(y-3) (7 y-1) = 0

So sin theta-3=0 or 7sin theta-1=0

May 2nd, 2015

Let's throw out the imaginary case, sin theta=3

so we get that sin theta=1/7 again, but this time it is a little neater. Now, we ned to determine when that happens. We know we have a 1, sqrt(48), 7 triangle. Which is not pretty. so, now how to make it any nicer.... hmmm

Oh we get to round! that is convenient! So theta=0.143 +2kpi

That gives us every revolution. So now we need to see if any other angles can have a sine of 1/7

May 2nd, 2015

So sine is positive in the first quad and second. We now need the value of that second quadrant angle. So we get it by doing (pi-0.143) So our second answer is