Description
Cover sheet (front page)
- title of Lab
- class/ section
- Your Name
- Professor's Name
Introduction (next page)
- Summary in your own words of the Theory/Introduction of Lab
Data (If you have the Lab manual, you may hand-write answers as long as they are legible)
- chart/ table/ excel spreadsheet
- calculations (if any)
Analysis
- Questions (either type the answers in complete sentences or type the Question with the answer below it)
Conclusion
-Summary
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Explanation & Answer
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Simple Harmonic Motion- Mass on spring
Class/ section
Your Name
Professor's Name
Introduction
The purpose of the experiment was to determine the spring constant K using Hooke’s
Law. The objects were to determine the spring constant k of a spring by measuring the
elongation versus applied force, determine the spring constant k from measurements of the
period T of oscillation for the different values of mass and investigate the dependence of the
period T of oscillation of a mass on a spring on the value of the mass and on the amplitude of the
motion. According to Newton’s second law, the net force acting on the body will cause the body
to vibrate back and forth around the system equilibrium, this is the simple harmonic motion.
Data
Data
Table 1
M (kg)
Mg (N)
y (m)
K (N/m)
r
0.05
0.49
3.3
5.656
0.9995
0.1
0.98
6.8
0.15
1.47
10.1
0.2
1.96
0.25
2.45
9
Data
Table 2
16.9
A (cm)
∆t₁(s)
∆t₂(s)
∆t₃(s)
∆t
αt (s)
T(s)
2
8.36
8.29
8.23
8.294
0.065
0.829
4
8.42
8.5
8.49
8.47
0.044
0.847
6
8.65
8.52
8.59
8.587
0.065
0.859
8
8.6
8.63
8.72
8.65
0.062
0.865
10
8.66
8.72
8.7
8.693
0.031
0.869
12
8.7
8.69
8.86
8.75
0.095
0.875
Data
Table 3
M (kg)
∆t₁(s)
∆t₂(s)
∆t₃(s)
∆t
αt (s)
T(s)
T²(s²)
0.05
3.99
3.23
4.09
3.77
0.47
0.377
0.114
0.1
5.63
5.4
5.76
5.596
0.182
0.559
0.312
0.15
6.69
6.33
6.76
6.593
0.231
0.659
0.434
0.2
7.86
7.1
7.31
7.423
0.392
0.742
0.551
0.25
8.36
7.69
8.1
8.05
0.338
0.805
0.648
Slope= 0.375
Intercept= -0.0044
K= 105.275
C=
0.694
r= 0.98
%Diff= 6.04
Y (m)
Table 1
18
16
14
12
10
8
6
4
2
0
y = 6.9796x - 0.08
R² = 0.9995
0
0.5
1
1.5
2
2.5
3
Mg (N)
Table 2
0.1
y = 0.2306x - 0.1374
R² = 0.0318
0.09
0.08
0.07
A
0.06
0.05
0.04
0.03
0.02
0.01
0
0.82
0.83
0.84
0.85
T
0.86
0.87
0.88
Table 3
0.3
0.25
y = 0.3749x - 0.0044
R² = 0.98
M (kg)
0.2
0.15
0.1
0.05
0
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
T²
Analysis
PRE-LABORATORY ASSIGNMENT
1. Describe in words and give an equation for the kind of force that produces simple harmonic
motion.
This is the equation for simple harmonic motion y = A cos(wt+∅). it can be described by a single
sine or cosine function of time.
2. Other than the type of force that produces it, what characterizes simple harmonic motion?
Displacement and amplitude also characterizes simple harmonic motion.
3. A spring has a spring constant k = 8.75 N/m. If the spring is displaced 0.150 m from its
equilibrium position, what is the force that the spring exerts? Show your ...
Review
Review
