Find the equation (in slope -intercept form) for the line through (2,-5) that is parallel to 2x-3y=5.

Evaluate the discriminant for each equation, and use it to determine the number of real solutions to the equation. 2x^2-3x+10=0.

Find all real or imaginary solutions to each equation. Use the method of your choice on each problem. 2x^2-11x+5=0 and 2/x-2-3/x+2=1/2

2x^2-3x+10=0.

2) delta=(-3)²-4*2*10= 9 - 80 = - 71 <0 so inexeste solution in IR

3) 2x^2-11x+5=0 so delta= (-11)²- 4*2*5 = 81 > 0

so :: x1 = (11 - sqrt(81))/4 = 2/4 = 1/2

x2 = (11 + sqrt(81))/4 = 20/4 = 5

for : 2/x-2-3/x+2=1/2 => x²+2x-22=0

so delta= 2² + 88 = 92

x1= (-2- sqrt(92))/2

x1= (-2+ sqrt(92))/2

Sorry i am forget the first :

1) the equation is : y=0,665x - 3,67

Good luck

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Okay I will thank you!!

Enjoy with the solution

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