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Calculate the solubility

label Chemistry
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Calculate the solubility of Ag2CrO4 (Ksp = 9.0 × 10–12) in a 0.021 M AgNO3 solution.

Apr 6th, 2015

DATA:

Concentration of Ag2CrO4 = 0.21 M

Ksp of Ag2CrO4 = 9.0*10-12

Solubility of Ag2CrO4 =?

SOLUTION:

Ag2CrO4 --------- Ag2+ + CrO42-

Ksp = [Ag+]2 [CrO42-]

Let, S is the solubility of CrO42- in the solution, so;

Ksp= S2 * S

9.0*10-12 = S3

S = 2.0800*10-4 M

The solubility for CrO42- will be;

[CrO42-] = 2.0800*10-4 M

And for Ag+ will be;

[Ag+] = 2 * 2.0800*10-4

  = 4.160*10-4 M


May 3rd, 2015

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Apr 6th, 2015
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