# java standard deviation

May 3rd, 2015
Anonymous
Category:
Programming
Price: \$5 USD

Question description

```/*
* Write an application that creates an int array of
* size 1000000, assigns a random integer between + and
* -10000 to each and computes the mean and
* standard deviation as decimal values.
* Print those to the user.
*
* Mean:
* (sum of all values) / (number of values)
*
* Standard Deviation:
* The square root of
*    the average of
*      the squared differences of
*         each value from the mean.
*
*/

public class StandardDeviation{
public static void main(String[] args){

int[] values = new int[1000000];
final int MIN_VALUE = -10000;
final int MAX_VALUE = 10000;
double valuesSum = 0.0, sqDiffSum = 0.0, mean, standardDev;

// Set each element in values equal to a random
// integer between MIN_VALUE and MAX_VALUE

// Compute the sum of all elements in values,
// such the sum gets stored in valuesSum

// Compute the mean (average) of all values
// and store in the variable mean

// Compute the sum of the squared differences
// of each value from the mean.  Conceptually,
// this looks like:
//    (first - mean)^2 +
//    (second - mean)^2 +
//    (third - mean)^2 +
//    ....... +
//    (last - mean)^2 +

// Compute the standard deviation, which is the
// square root of the result of dividing the sum of
// squared differences by the total number of values

System.out.println("Mean:               " + mean);
System.out.println("Standard Deviation: " + standardDev);

}

private static int randomIntInRange(int low, int high) {

int multiplier = high - (low - 1);
return (int)(Math.random() * multiplier) + low;

}

}```
output

```Mean:               -3.77569
Standard Deviation: 5779.955079273639```

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