Solving for pH of a strong acid

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Perchloric Acid(HClO4) is a very strong acid. When 10.0mL of 9.20M HCl is diluted to a final volume of 10.0L, what will be the pH of the resultant solution ?

May 3rd, 2015

M1V1 = M2V2

(9.20 mol/L) (0.10 L) = (x) (10 L)

x = 0.0092 M

pH = - log [.0092]

     = 2.036

Please let me know if you have any other questions and best me if you are satisfactory.   




May 3rd, 2015

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