differentiate y=log(4+cosx)

let y=log (4 + cos x) then dy/dx =d(log (4 + cos x) )/dx

apply chain rule of differetiation dy/dx=1/cosx * d(cosx)/dx dy/dx=1/cosx *(-sinx)*d(x)/dx dy/dx= 4 (-sin x/cos x)dy/dx= 4 -tan x

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