##### specific heat problem

 Physics Tutor: None Selected Time limit: 1 Day

I need to find the specific heat of copper using this formula - mass(specific heat)(change in temperature) + (mass)(specific heat)(change in temperature)=0

the mass of water is .1kg sh is 4180 j/kg temperature change - 2 for copper the numbers are mass .018 kg sh- need to find temp change- 76 for my answer i get .611 but it needs to be around .386 and i don't know what i'm doing wrong! please help!

May 3rd, 2015

set up heat transferred for (copper+ water)

Q = m1 x sh1 x tc1 + m2 x sh2 x tc2
0 = (.018)(sh1)(-76)+(.1kg)(4180j/kg)(-2)
0 = (-1.368)(sh1) + (-836)
you have a number wrong

May 3rd, 2015

thanks for your help! maybe when we did the experiment we wrote down the wrong results! i'm not sure because those are my numbers. i appreciate the help!

May 3rd, 2015

welcome

May 3rd, 2015

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May 3rd, 2015
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May 3rd, 2015
Dec 4th, 2016
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