Chemistry question that i really need help with

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  1. Given:

    Cu2O(s) + O2(g→ 2CuO(s)ΔH° = –144 kJ
    Cu2O(s→ Cu(s) + CuO(s)ΔH° = +11 kJ

    Calculate ΔH for the reaction, Cu(s) + O2(g) → CuO(s).


    a.

    b.

    c.

    d.

    e.
May 4th, 2015

Cu2O(s) + O2(g) → 2CuO(s)           ΔH1 

Cu2O(s) → Cu(s) + CuO(s)               ΔH2

subtract  this two equation  the final equation will become 

 Cu(s) + O2(g) → CuO(s).        ΔH

So ΔH = (ΔH1- ΔH2)

           



 Plz give me ΔH1 and ΔH2

 so that I can give you exact answer 



May 4th, 2015

1 -144kj

2. +11 kj

May 4th, 2015

ΔH = (ΔH1- ΔH2)

        = -144-11= -155kj

answer  will be C 

May 4th, 2015

thank you!

May 4th, 2015

welcome here 

May 4th, 2015

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