Calculate ΔH for the reaction, Cu(s) + O2(g) → CuO(s).
Cu2O(s) + O2(g) → 2CuO(s) ΔH1
Cu2O(s) → Cu(s) + CuO(s) ΔH2
subtract this two equation the final equation will become
Cu(s) + O2(g) → CuO(s). ΔH
So ΔH = (ΔH1- ΔH2)
Plz give me ΔH1 and ΔH2
so that I can give you exact answer
2. +11 kj
ΔH = (ΔH1- ΔH2)
= -144-11= -155kj
answer will be C
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