Given:

Calculate ΔH for the reaction, Cu(s) + O_{2}(g) → CuO(s).

–299 kJ

–166 kJ

–155 kJ

+155 kJ

+299 kJ

Cu2O(s) + O2(g) → 2CuO(s) ΔH1

Cu2O(s) → Cu(s) + CuO(s) ΔH2

subtract this two equation the final equation will become

Cu(s) + O2(g) → CuO(s). ΔH

So ΔH = (ΔH1- ΔH2)

Plz give me ΔH1 and ΔH2

so that I can give you exact answer

1 -144kj

2. +11 kj

ΔH = (ΔH1- ΔH2)

= -144-11= -155kj

answer will be C

thank you!

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