how to set this up into an equation

Mathematics
Tutor: None Selected Time limit: 1 Day

Rectangular parking lot has length that is 5 yards less than twice it width. The area =88 square feet. What are the dimensions?

May 4th, 2015

A = Length * Width

88 Sq fet = w yards * (2w-5) yards

29.33 yards = 2w^2 - 5w yards

29 1/3 yards = 2(w^2 - 5/2w)

29.33/2 = w^2 - 5/2w

29.33/2 + 25/16 = w^2 - 5/2w + 25/16 (complete the square)

234.64.16 + 25/16 = (w - 5/4)^2

259.64/16 = (w-5/4)^2

SQRT 16.2275 = w- 54

4.02 = w - 54

4.02 + 54 = w

56.02 yards = w

L = 2(56.02 -5)

L = 2 (51.02)

L = 102.04

W = 56 yards

L = 102 yards



May 4th, 2015

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
May 4th, 2015
...
May 4th, 2015
Dec 6th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer