how to set this up into an equation

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Rectangular parking lot has length that is 5 yards less than twice it width. The area =88 square feet. What are the dimensions?

May 4th, 2015

A = Length * Width

88 Sq fet = w yards * (2w-5) yards

29.33 yards = 2w^2 - 5w yards

29 1/3 yards = 2(w^2 - 5/2w)

29.33/2 = w^2 - 5/2w

29.33/2 + 25/16 = w^2 - 5/2w + 25/16 (complete the square)

234.64.16 + 25/16 = (w - 5/4)^2

259.64/16 = (w-5/4)^2

SQRT 16.2275 = w- 54

4.02 = w - 54

4.02 + 54 = w

56.02 yards = w

L = 2(56.02 -5)

L = 2 (51.02)

L = 102.04

W = 56 yards

L = 102 yards



May 4th, 2015

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