Approximating solution of b(x)=c(x), both given.

Algebra
Tutor: None Selected Time limit: 1 Day

Approximate the solution of the equation b(x)=c(x), given b(x)=log(2x) and c(x)=5-e^x. Explain how you found your answer.

May 4th, 2015

let log(2x)=5-e^x

log2+logx=5-e^x

lnx+e^x=5-log2=4.7

x is approximately 1.38

you can also draw out two graphs, that is easier to find, you just have to find the intersection point.

Let me know if you have any questions



May 4th, 2015

I'm not sure how we went from step 2 to step 3.

May 4th, 2015

hold up for a sec

May 4th, 2015

what I did was that lnx+e^x=5-log2=4.7, lnx=e^x-4.7

which means e^x move down to 4.7 units on the graph

So I drew lnx and e^x-4.7 on the same graph, found the intersection point, and that's the approximate value

May 4th, 2015

I'm gonna have to work on my skills with these some more lol but thanks XD

May 4th, 2015

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