Description
Explanation & Answer
Let D denote Delta, B for Beta, and S for Sigma.
7D + 15B + 5S = 128 (for painting)
3D + 7B + 5S = 88 (for drying)
4D + 5B + 5S = 86(for polishing)
Let's eliminate S first.
7D + 15B + 5S = 128
-1[3D + 7B + 5S = 88]-1
4D +8B =40(equation 1)
-1[4D + 5B + 4S = 86]-1
7D + 15B + 5S =128
3D +10B =42 (equation 2)
Let's now use equation 1 and eqaution 2 to solve for thevalues of D and B.
In solving for D and B, let's eliminate D first.
4D +8B =40 also equals D +2B =10
3(10-2B) +10B =42
30 - 6B +10B = 42
4B = 12
B = 3.
D+2(3)=10
D= 4.
Now, let's solve for S.
7(4) + 15(3) + 5S = 128
28 + 45 + 5S = 128
5S = 55
S = 11.
Therefore, Epsilon Motor Company produces 4 Deltas, 3 Betas, and 11 Sigmas in a month.
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