This is in the category of analytic trigonometry, and needs to be verified.

label Calculus
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May 4th, 2015

We rewrite the expression differently making sin^2(x) appears

sin^5(x)*cos^2(x)=sin(x)*sin^2(x)*sin^2(x)*cos^2(x)

We remplace sin^2(x) by 1 - cos^2(x) as it's equal

so sin^5(x)*cos^2(x)=sin(x)*(1-cos^2(x))*((1-cos^2(x))*cos^2(x)

=sin(x)*(1-cos^2(x))(cos^2(x)-cos^4(x))=sin(x)(cos^2(x)-cos^4(x)-cos^4(x)+cos^6(x))

=sin(x)(cos^2(x)-2cos^4(x)+cos^6(x))

That's it. 


May 4th, 2015

Thanks man

May 4th, 2015

Thanks man

May 4th, 2015

You are welcome 

May 4th, 2015

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