Area=Lenght . Width
Let's call x the width. As the lenght is 8 yards greater than the width, we can express lenght as x+8
So we have Area = (x+8).x
We just have to solve 560 = (x+8)*x
Then we calculate the discriminant D
(In the general case of the equation a.x^2+b.x+c=0, D=b^2-4.a.c)
Solutions are x1=(-8+square root(2304))/(2*1) or x1=(-8-square root(2304))/(2*1)
x1=(-8+48)/2 or x2=(-8-48)/2
x1=40/2=20 or x2=-28
x2 is a negative solution so we have to remove it. The only good solution is x1 and the width we are seeking is 20 yards.
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