Confidence interval $ margin of error question

label Statistics
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schedule 1 Day
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45 workers had an average salary of $52,340 if the standard deviation is $16,920 what is the 90% confidence interval for the population mean and margin of error

May 4th, 2015

u=x~+or-Za/_n

=52340+or-1.96.16920/_45

=52340+-4943.6779=47,396.3221 or 57,283.6779

margin of error=4,944.35

May 4th, 2015

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May 4th, 2015
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May 4th, 2015
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