A 8.2 m long elastic band is used to launch a toy glider. Once stretched to a length of 38 m, the band releases 1.6 J of elastic potential energy when you let it contract 0.051 m. What forward force is the band exerting on the toy glider?

Let's note Epe the elastic potential energy,

you can write that Epe=1/2*k*x^2 where x is the distance stretched and k the elastic constant

so k=2*Epe/x^2, thus k=2*1,6/(38-8,2)^2=3,60.10^-3 N/m

Now let see the force, the value of the force is equal to F=k*|x| (using vector you have F=-kx) where now x=0,051 m

so F=1,84.10^-4 N

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