what volume in ml of 9.76M hydrochloric acid solution should be used to prepare 2.00L of .400M HCL

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chapter 16 intro to chem

May 4th, 2015

M1V1 =M2V2

9.76 V(HCl) = 0.4 *2.0 

V(HCl) = 0.4 *2.0 /9.76

              = 0.081 L = 81 mL


Regarding any doubt plz let me know 

May 4th, 2015

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