you need to an aqueous solution of .123M manganese (ii) acetate (acetate ion, C2H3O2) using a 250 ml volumetric flask. How much solid manganese (ii) acetate should you add?
number of moles= molar mass/volume
mass= 0.123*250= 30.75
the solid will be 30.75g
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?