can someone please help me

label Chemistry
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how many grams of aluminum nitrate must be dissolved in 5.00x10^2 gm of water to prepare 0.121m solution of the salt? 

May 4th, 2015

Molarity=Moles/Vol in L 
Moles=Molarity*Vol in L 

=0.121x0.05

=6.05x10^-03

Mass is gm=Moles x Mass no

=6.05x10^-03x212.99

=1.29 grams


May 4th, 2015

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