x to the second power+10x+16=0

x^2+10x+16 =0

Now choose two numbers such that the sum is 10 and product is 16. so the numbers are 8 and 2.

So x^2+10x+16 =0 can be written as (x+8) (x+2) =0

So either (x+8) =0 or (x+2) =0

x = -8, -2

Please let me know if you have any other questions and best me if you are satisfactory.

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