What is the final volume of a solution of 0.1128 M Na3PO4(aq) prepared from 33.8 g Na3PO4(s)?
molecular weight of Na3PO4 =163.94
moles = 33.8/163.94= 0.2061
Molarity = moles/volumes(L)= 0.2061/V
0.1128 = 0.2061/V
V= 0.2061/0.1128 = 1.82 L
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