Suppose 20% of all adults in a small town live alone and 8% of all adults live alone and have at least one pet. What is the probability that a randomly selected adult from this town has at least one pet given the adult lives alone?

It is 0.4.....................................................................................................................................

Can you please show me how you got that answer

Here P(B)=0.2, P(A and B) = 0.08

So

P(A\B)=P(A and B)\P(B)= 0.08/0.2= 2/5 = 0.4

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