perimeter of triangle ABC=AB+BC+AC

AB=AE+EB=6+4=10

Point G is a point of cross-section of bisectors of the triangle ABC

So:

EB=BF=4

BC=BF+FC=7+4=11

AD=AE=6

DC=FC=7

AC=AD+DC=6+7=13

perimeter of triangle ABC=AB+BC+AC=10+11+13=34

Answer: 34

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