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I toss a coin repeatedly. The coin is unfair and P(H)=1/3. The game ends the first time that two consecutive heads (HH) or two consecuative tails (TT) are observed. I win if the HH is observed and i lose if the TT is observed. For example, if the outcome is HTHTT, i lose. On the other hand, if the outcome is THTHTHH, i win. Find the probability that i win

May 5th, 2015

7/28.........................however, the number of tosses is not well defined. If there is no limit to the number of tosses, you could go even ten tosses without winning or losing.......................you may clarify please!!

May 5th, 2015

Can you explain how you got the 7/23? (i will tip you for this so its not a waste of your time) And i wish i could clarify more but that is the entire question and all the info i have

May 5th, 2015

okay...a coin is unfair such the chances of getting head are limited to 1/3 instead of the usual 1/2. i took the first 4 tosses of the coin, so here is the outcome;

1/3 getting the first head, then the other 1/3 for subsequent head.(we close at that point since the outcome is HH)..............................(1/3x1/3)=1/9

still when we get the first head(1/3) we may land on the T the next toss,then on the third toss we get two heads............................(1/3x2/3x1/3x1/3)=2/81

.........................does this look impress dear....hope you're getting before we conclude...you there?

May 5th, 2015

wait i thoguht you said it was 7/23?? is that not anymore

May 5th, 2015

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May 5th, 2015
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May 5th, 2015
Dec 9th, 2016
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