copper at 25.0oC. What would the final temperature of the copper be (in oC) if it absorbed 150 J of heat?
Let's call q the heat that is transferred, DT the change in temperature, C the heat capacity and m the mass of the copper cube
We have the following relationship :
q=DT*C*m so DT=q/(C*m)
Numerically DT= 150/(0,38*25)=15,8 °C
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