copper at 25.0^{o}C. What would the final temperature of the copper be (in ^{o}C) if it absorbed 150 J of heat?

Let's call q the heat that is transferred, DT the change in temperature, C the heat capacity and m the mass of the copper cube

We have the following relationship :

q=DT*C*m so DT=q/(C*m)

Numerically DT= 150/(0,38*25)=15,8 °C

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up