Let us consider 100 g of compound.
Mass of nitrogen=14.79g
Moles of nitrogen=14.79/14=1.056mol
Mass of oxygen=50.68g
Moles of nitrogen=50.68/16=3.1675mol
Mass of zinc=14.79g
Moles of nitrogen=34.79/65=0.532mol
Would the answer change if zinc is 34.53%.
zinc is already 34.53%, any composition change may result in change of formula.
When I'm looking at the problem you worked out I see that you put zinc at 14.79 why is that, should it not be 34.53.
Oh! that is just a typo error, next line I have taken it 34.53. It should have been 34.53 g.
Ok thanks I don't see it I see 34.79 I needed 34.53. Thank you for your help.
us consider 100 g of compound.
very small change in mass doesn’t reflect in empirical formula.
Sorry how is O6 and not O3
Because, 3.1675/0.531=5.97 equivalent to 6. So, every no need to be converted to integar.
Okay thank you so much. Can I pay you for your troubles.
Ya, is you wish. I would be very happy to help you again.
do you have more doubt? Plz contact me on message.
No thank you I am just working it out to see if I come up with the same answer you did.
My final answer was N:1.0552 O:3.1677 ZN:0.5280
I am dividing all the numbers by 1.0552
No. Always divide by smallest number, ie 0.5280. And round it to nearesnearest integar.
Ok thank you will rework my problem.
Plz message me for more help.
Ok thank you for your help. I finally got the same answer you have. How do I pay you?
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