Can someone please help me with these chemistry problem. Thanks.

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fnyyl01

Science

Description

An unknown compound is analyzed and found to be composed of 14.79% nitrogen, 50.68% oxygen, and 34.53% zinc. Calculate the empirical formula for the compound.

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Explanation & Answer

Let us consider 100 g of compound.

Mass of nitrogen=14.79g

Moles of nitrogen=14.79/14=1.056mol

Mass of oxygen=50.68g

Moles of nitrogen=50.68/16=3.1675mol

Mass of zinc=14.79g

Moles of nitrogen=34.79/65=0.532mol

Simple ratio,

N:O:Zn=1.056:3.1675:0.532

=2:6:1

Empirical formula=ZnN2O6



Anonymous
Just what I was looking for! Super helpful.

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