A 30% solution of fertilizer is to be mixed with a 60% solution of fertilizer in order to get 120 gallons of a 50% solution. How many gallons of the 30% solution and 60% sould should be mixed?

Let x gallon of 30% solution and y gallon of 60% solution be mixed.

Then,

x+y=120 …………….(1)

30% of x+60% of y=50% of 120

0.3x+0.6y=60 ……………..(2)

Solving (1) and (2),

x=40

y=80

So we mix 40gallon 30% solution

and 80gallon 60% solution.

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