What is the minimum incident angle, θi,
at which a light ray can enter the prism so that it does not undergo
total internal reflection upon exiting the prism? Assume that the index
of refraction is 1.51
n1 (air) = 1.00n2 (Plexiglas) = 1.51
no angle of incident is given
n2Sin(Theta) = n1Sin 90
Theta = Sin -1(0.66) = 41.29
thata > 41.29 for TIR.
Regarding any doubt plz let me know.
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