(x^2 - 4) / (x-2) if x< 2

f(x)= ax^2 - bx + 3 if 2 </= x < 3

4x - a + b if x =/> 3

we need to let f(x) continuous at x = 2 and x = 3

x = 2-

f(x) = (x^2-4)/(x-2) = x+2 = 4

x=2+

f(x) = 4a-2b+3 = 4

at 3-

f(x) = 9a-3b+3

at 3+

f(x) = 12-a+b =9a-3b+3

so

4a-2b=1

10a-4b=9

a = 7/2

b = 13/2

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