Take 2x outside from the first two terms since 2x is a common factor and
3 from the 3rd and 4th terms since 3 is a common factor
6xy-4x+9y-6 = 2x(6xy/2x -4x/2x) + 3(9y/3-6/3)
= 2x(3y-2) + 3(3y-2)
Since (3y-2) is a common factor, take (3y-2)
= (3y-2) (2x+3)
Please let me know if you have any questions and best me if you are satisfactory.
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