##### Can someone help me show work please

label Mathematics
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May 7th, 2015

If a secant segment and tangent segment are drawn to a circle from the same external point, the product of the length of the secant segment and its external part equals the square of the length of the tangent segment.

So,

$RS^2 = RQ*RT\\ RS^2 = (RT+TQ)*3\\ RS^2 = (3+9)*3\\ RS^2 = 12*3\\ RS^2 = 36\\ RS=\sqrt{36}\\ RS=6$

May 7th, 2015

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May 7th, 2015
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May 7th, 2015
Jun 24th, 2017
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