Find the SDlope of the tangent line to the graph of the polar equation r=sin(tetta) at the point where Theta=Pi/3
we take f(tetta)=sin(tetta)
we know : y= f ' (x0)(x-x0) + f(x0)
we have x0=pi/3 so
and f '(pi/3) = 1/2
so : y = 1/2 (x - pi/3) + sqrt(3)/2
so : y= (1/2)x - pi/6 + sqrt(3)/2 is the equation of the tangent at pi/3 of the equation r
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