Find the SDlope of the tangent line to the graph of the polar equation r=sin(tetta) at the point where Theta=Pi/3

we take f(tetta)=sin(tetta)

we know : y= f ' (x0)(x-x0) + f(x0)

we have x0=pi/3 so

f(pi/3)= sqrt(3)/2

and f '(pi/3) = 1/2

so : y = 1/2 (x - pi/3) + sqrt(3)/2

so : y= (1/2)x - pi/6 + sqrt(3)/2 is the equation of the tangent at pi/3 of the equation r

Good luck

and please when you put any question on studypool invite me , i will give you the best answer

i want to be the Top tutor so help me as you can

your friends Karim

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up