a is a factor of c , so c = ka for some integer k (1)
a + b = c
So b = c -a
b = ka -a Using (1) and replacing c
b = (k-1) a Taking out a as common factor
Since k is an integer, k-1 is also an integer, call it m
b = ma (where m = k-1)
b is a multiple of a , so a is a factor of b
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