a) Z(106 lb bag) = 106 - 100 / 15 = 0.4

Z(94 lb bag) = 94 - 100 / 15 = -0.4

P(-0.4 < Z < 0.4) = 0.6554 - 0.3446 = 0.3108

b) the standard error of the mean is 15/sqrt(36) = 15/6 = 2.5

c) Z value of mean of sample being 106:

Z = 106-100 / 15/6 = 2.4

Z value of mean of sample being 94:

94-100/ 15/6 = -2.4

thefore, P(-2.4 <Z<2.4) = 0.9918 - .0082 = 0.9836

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up