# Pre-calculus trigonometric functions

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Question description

Pre-calculus trigonometric functions. Evaluate the expression: three multiple choice questions.

Evaluate the expression. sin(90 A) B) C) D) sin( cos( tan( cot( A B C D )*tan( ) ) ) ) )*sec( ) Evaluate the expression. tan(90- )*tan( A) 1 B) 0 C) sec( ) D) cot( ) A B C D )*sec( )

jesusale932
School: New York University

First we need to find DC

π‘ππΞΈ =

π·πΆ
π΅πΆ

π‘ππ52 =

π·πΆ
8

π·πΆ = π‘ππ52 β 8 = 10.24
Then, we are going to find distance ABC:
tanβ‘(πΌ) =

π·πΆ
π΄π΅πΆ

tanβ‘(42) =

10.24
π΄π΅πΆ

π΄π΅ + π΅πΆ =

10.24
= 11.4
tanβ‘(42)

So, AB will be the difference between ABC β BC = AB
π΄π΅ = 11.4 β 8

Evaluate the expression.
sin(90 A)
B)
C)
D)

sin(
cos(
tan(
cot(

)*tan(

)*sec(

)

)
)
)
)

A
B
C
D

sin(π’ Β± π£) = sin π’ cos π£ Β± sin π£ cos π’

sin(90 β π) = sin 90 cos π β sin π cos 90
sin(90 β π) = cos π
Substituting we get,
sin(90 β π) β π‘ππ(π) β π ππ(π) = ππ...

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Anonymous
Outstanding Job!!!!

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