solve trigonometric equation analytically

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solve for values of x for 0<= x < 2pi

sin^2 x + sin x = 0

May 10th, 2015

we have : sin^2 x + sin x = 0

sin(x)(sin(x) + 1) = 0 

so : sin(x) = 0  or  sin(x) + 1 = 0

so : sin(x) = 0  =>  x= 0 + 2Kpi 

and for : sin(x) + 1 = 0

so : sin(x) = -1  => sin(x) = sin(3pi/2)  so : x = 3pi/2 + 2Kpi  

Good luck 

and please if you have any other homework please invite me to i give you the best answer 

May 10th, 2015

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